Day 11: Plutonian Pebbles
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I had a very similar take on this problem, but I was not caching the results of a blink for a single stone, like youre doing with
subtree_pointers
. I tried adding that to my solution, but it didn’t make an appreciable difference. I think that caching the lengths is really the only thing that matters.C#
static object Solve(Input i, int numBlinks) { // This is a cache of the tuples of (stoneValue, blinks) to // the calculated count of their child stones. var lengthCache = new Dictionary<(long, int), long>(); return i.InitialStones .Sum(stone => CalculateUltimateLength(stone, numBlinks, lengthCache)); } static long CalculateUltimateLength( long stone, int numBlinks, IDictionary<(long, int), long> lengthCache) { if (numBlinks == 0) return 1; if (lengthCache.TryGetValue((stone, numBlinks), out var length)) return length; length = Blink(stone) .Sum(next => CalculateUltimateLength(next, numBlinks - 1, lengthCache)); lengthCache[(stone, numBlinks)] = length; return length; } static long[] Blink(long stone) { if (stone == 0) return [1]; var stoneText = stone.ToString(); if (stoneText.Length % 2 == 0) { var halfLength = stoneText.Length / 2; return [ long.Parse(stoneText.Substring(0, halfLength)), long.Parse(stoneText.Substring(halfLength)), ]; } return [stone * 2024]; }
Yep, it is just a dynamic programming problem really.