Day 3: Mull It Over

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FAQ

  • Quant@programming.dev
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    3 months ago

    Uiua

    Regex my beloved <3

    Run with example input here

    FindMul  regex "mul\\((\\d+),(\\d+)\\)"
    
    PartOne  (
      &rs  &fo "input-3.txt"
      FindMul
      /+≡(×°⊟⋕⊏1_2)
    )
    
    IdDont  ⊗□"don't()"
    
    PartTwo  (
      &rs  &fo "input-3.txt"
      regex "mul\\(\\d+,\\d+\\)|do\\(\\)|don't\\(\\)"
      (IdDont.
        1⊃↘↙
        ⊗□"do()".
        ⊂↘1
      | IdDont.
        ≠⧻,
      )
      ▽♭=0⌕□"do()".
      (×°⊟⋕⊏1_2FindMul)
      /+
    )
    
    &p "Day 3:"
    &pf "Part 1: "
    &p PartOne
    &pf "Part 2: "
    &p PartTwo
    
  • LeixB@lemmy.world
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    3 months ago

    Haskell

    module Main where
    
    import Control.Arrow hiding ((+++))
    import Data.Char
    import Data.Functor
    import Data.Maybe
    import Text.ParserCombinators.ReadP hiding (get)
    import Text.ParserCombinators.ReadP qualified as P
    
    data Op = Mul Int Int | Do | Dont deriving (Show)
    
    parser1 :: ReadP [(Int, Int)]
    parser1 = catMaybes <$> many ((Just <$> mul) <++ (P.get $> Nothing))
    
    parser2 :: ReadP [Op]
    parser2 = catMaybes <$> many ((Just <$> operation) <++ (P.get $> Nothing))
    
    mul :: ReadP (Int, Int)
    mul = (,) <$> (string "mul(" *> (read <$> munch1 isDigit <* char ',')) <*> (read <$> munch1 isDigit <* char ')')
    
    operation :: ReadP Op
    operation = (string "do()" $> Do) +++ (string "don't()" $> Dont) +++ (uncurry Mul <$> mul)
    
    foldOp :: (Bool, Int) -> Op -> (Bool, Int)
    foldOp (_, n) Do = (True, n)
    foldOp (_, n) Dont = (False, n)
    foldOp (True, n) (Mul a b) = (True, n + a * b)
    foldOp (False, n) _ = (False, n)
    
    part1 = sum . fmap (uncurry (*)) . fst . last . readP_to_S parser1
    part2 = snd . foldl foldOp (True, 0) . fst . last . readP_to_S parser2
    
    main = getContents >>= print . (part1 &&& part2)
    
  • rwdf@lemmy.world
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    edit-2
    3 months ago

    Elixir

    First time writing Elixir. It’s probably janky af.

    I’ve had some help from AI to get some pointers along the way. I’m not competing in any way, just trying to learn and have fun.

    ~~Part 2 is currently not working, and I can’t figure out why. I’m trying to just remove everything from “don’t()” to “do()” and just pass the rest through the working solution for part 1. Should work, right?

    Any pointers?~~

    edit; working solution:

    defmodule Three do
      def get_input do
        File.read!("./input.txt")
      end
    
      def extract_operations(input) do
        Regex.scan(~r/mul\((\d{1,3}),(\d{1,3})\)/, input)
        |> Enum.map(fn [_op, num1, num2] ->
          num1 = String.to_integer(num1)
          num2 = String.to_integer(num2)
          [num1 * num2]
        end)
      end
    
      def sum_products(ops) do
        List.flatten(ops)
        |> Enum.filter(fn x -> is_integer(x) end)
        |> Enum.sum()
      end
    
      def part1 do
        extract_operations(get_input())
        |> sum_products()
      end
    
      def part2 do
        String.split(get_input(), ~r/don\'t\(\)[\s\S]*?do\(\)/)
        |> Enum.map(&extract_operations/1)
        |> sum_products()
      end
    end
    
    IO.puts("part 1: #{Three.part1()}")
    IO.puts("part 2: #{Three.part2()}")
    
    
    • vole@lemmy.world
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      3 months ago

      Part 2 is currently not working, and I can’t figure out why. I’m trying to just remove everything from “don’t()” to “do()” and just pass the rest through the working solution for part 1. Should work, right?

      I think I had the same issue. Consider what happens if there isn’t a do() after a don’t().

      • rwdf@lemmy.world
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        3 months ago

        Ah, yes, that’s it. The lazy solution would be to add a “do()” to the end of the input, right? Haha

        • rwdf@lemmy.world
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          3 months ago

          It was actually a line break that broke the regex. Changing from a “.” to “[\s\S]” fixed it.

  • Sleepless One@lemmy.ml
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    3 months ago

    Rust

    use crate::utils::read_lines;
    
    pub fn solution1() {
        let lines = read_lines("src/day3/input.txt");
        let sum = lines
            .map(|line| {
                let mut sum = 0;
                let mut command_bytes = Vec::new();
                for byte in line.bytes() {
                    match (byte, command_bytes.as_slice()) {
                        (b')', [.., b'0'..=b'9']) => {
                            handle_mul(&mut command_bytes, &mut sum);
                        }
                        _ if matches_mul(byte, &command_bytes) => {
                            command_bytes.push(byte);
                        }
                        _ => {
                            command_bytes.clear();
                        }
                    }
                }
    
                sum
            })
            .sum::<usize>();
    
        println!("Sum of multiplication results = {sum}");
    }
    
    pub fn solution2() {
        let lines = read_lines("src/day3/input.txt");
    
        let mut can_mul = true;
        let sum = lines
            .map(|line| {
                let mut sum = 0;
                let mut command_bytes = Vec::new();
                for byte in line.bytes() {
                    match (byte, command_bytes.as_slice()) {
                        (b')', [.., b'0'..=b'9']) if can_mul => {
                            handle_mul(&mut command_bytes, &mut sum);
                        }
                        (b')', [b'd', b'o', b'(']) => {
                            can_mul = true;
                            command_bytes.clear();
                        }
                        (b')', [.., b't', b'(']) => {
                            can_mul = false;
                            command_bytes.clear();
                        }
                        _ if matches_do_or_dont(byte, &command_bytes)
                            || matches_mul(byte, &command_bytes) =>
                        {
                            command_bytes.push(byte);
                        }
                        _ => {
                            command_bytes.clear();
                        }
                    }
                }
    
                sum
            })
            .sum::<usize>();
    
        println!("Sum of enabled multiplication results = {sum}");
    }
    
    fn matches_mul(byte: u8, command_bytes: &[u8]) -> bool {
        matches!(
            (byte, command_bytes),
            (b'm', [])
                | (b'u', [.., b'm'])
                | (b'l', [.., b'u'])
                | (b'(', [.., b'l'])
                | (b'0'..=b'9', [.., b'(' | b'0'..=b'9' | b','])
                | (b',', [.., b'0'..=b'9'])
        )
    }
    
    fn matches_do_or_dont(byte: u8, command_bytes: &[u8]) -> bool {
        matches!(
            (byte, command_bytes),
            (b'd', [])
                | (b'o', [.., b'd'])
                | (b'n', [.., b'o'])
                | (b'\'', [.., b'n'])
                | (b'(', [.., b'o' | b't'])
                | (b't', [.., b'\''])
        )
    }
    
    fn handle_mul(command_bytes: &mut Vec<u8>, sum: &mut usize) {
        let first_num_index = command_bytes
            .iter()
            .position(u8::is_ascii_digit)
            .expect("Guarunteed to be there");
        let comma_index = command_bytes
            .iter()
            .position(|&c| c == b',')
            .expect("Guarunteed to be there.");
    
        let num1 = bytes_to_num(&command_bytes[first_num_index..comma_index]);
        let num2 = bytes_to_num(&command_bytes[comma_index + 1..]);
    
        *sum += num1 * num2;
        command_bytes.clear();
    }
    
    fn bytes_to_num(bytes: &[u8]) -> usize {
        bytes
            .iter()
            .rev()
            .enumerate()
            .map(|(i, digit)| (*digit - b'0') as usize * 10usize.pow(i as u32))
            .sum::<usize>()
    }
    

    Definitely not my prettiest code ever. It would probably look nicer if I used regex or some parsing library, but I took on the self-imposed challenge of not using third party libraries. Also, this is already further than I made it last year!