Day 7: Bridge Repair

Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • You can send code in code blocks by using three backticks, the code, and then three backticks or use something such as https://topaz.github.io/paste/ if you prefer sending it through a URL

FAQ

  • Ananace@lemmy.ananace.dev
    link
    fedilink
    arrow-up
    0
    ·
    edit-2
    5 days ago

    Made a couple of attempts to munge the input data into some kind of binary search tree, lost some time to that, then threw my hands into the air and did a more naïve sort-of breadth-first search instead. Which turned out to be better for part 2 anyway.
    Also, maths. Runs in just over a hundred milliseconds when using AsParallel, around half a second without.

    C#
    List<(long, int[])> data = new List<(long, int[])>();
    
    public void Input(IEnumerable<string> lines)
    {
      foreach (var line in lines)
      {
        var parts = line.Split(':', StringSplitOptions.TrimEntries);
    
        data.Add((long.Parse(parts.First()), parts.Last().Split(' ').Select(int.Parse).ToArray()));
      }
    }
    
    public void Part1()
    {
      var correct = data.Where(kv => CalcPart(kv.Item1, kv.Item2)).Select(kv => kv.Item1).Sum();
    
      Console.WriteLine($"Correct: {correct}");
    }
    public void Part2()
    {
      var correct = data.AsParallel().Where(kv => CalcPart2(kv.Item1, kv.Item2)).Select(kv => kv.Item1).Sum();
    
      Console.WriteLine($"Correct: {correct}");
    }
    
    public bool CalcPart(long res, Span<int> num, long carried = 0)
    {
      var next = num[0];
      if (num.Length == 1)
        return res == carried + next || res == carried * next;
      return CalcPart(res, num.Slice(1), carried + next) || CalcPart(res, num.Slice(1), carried * next);
    }
    
    public bool CalcPart2(long res, Span<int> num, long carried = 0)
    {
      var next = num[0];
      // Get the 10 logarithm for the next number, expand the carried value by 10^<next 10log + 1>, add the two together
      // For 123 || 45
      // 45 ⇒ 10log(45) + 1 == 2
      // 123 * 10^2 + 45 == 12345
      long combined = carried * (long)Math.Pow(10, Math.Floor(Math.Log10(next) + 1)) + next;
      if (num.Length == 1)
        return res == carried + next || res == carried * next || res == combined;
      return CalcPart2(res, num.Slice(1), carried + next) || CalcPart2(res, num.Slice(1), carried * next) || CalcPart2(res, num.Slice(1), combined);
    }